Drakkith said:
Marcus or Chalnoth, is there a local redshift due to actual motion away from us equivalent to z=3 redshift? IE would an object moving away from us here in local space have the same redshift at a certain velocity?
To translate local velocities into doppler one uses the relativistic doppler shift formula
If β is the speed (as a fraction v/c of speed of light) then
1+z = sqrt((1+β)/(1-β))
so if you want the speed that would give a doppler shift (not a cosmological redshift but an actual doppler shift) of 3, then you have to set that sqrt = 1+3 = 4
so what's inside the sqrt must = 16.
And you can solve for β.
Let's see what that would be, in the example of shift=3 that you proposed.
16(1-β) = (1+β)
15 = 17β
β = 15/17 of the speed of light.
That is a purely special rel. thing, the calculation applies in local nonexpanding geometry and the speed you get has essentially nothing to do with expansion that occurs while light is traveling long distances.
As I'm sure you know but other readers might not, if you go here
http://www.einsteins-theory-of-relativity-4engineers.com/cosmocalc.htm
and plop 3 into the redshift box and press calculate then it tells you that the recession rate was 1.6 c when
the light was emitted and 1.5 c when the light was received here on earth.
The cosmological redshift is the result of all the expansion that was happening all while the light was in transit from there to here. It does not depend just on one instantaneous relative velocity, like doppler does.
That's obviously different from the doppler 15/17 c.