The expression for the age of the universe in a general cosmological model is:
T = \frac{1}{H_0} \int_0^1 \frac{da}{\sqrt{ \Omega_{k, 0} + \displaystyle \frac{\Omega_{m,0} }{a} + \displaystyle \frac{\Omega_{r,0} }{a^2}+ \Omega_{\Lambda,0} a^2 \right)}}}
Neglecting the radiation density, for the age to be equal to T = 1/H_0, it must hold that:
\mathcal{I}(\Omega_{m,0}, \Omega_{\Lambda,0}) = \int_0^1 \frac{da}{\sqrt{ \Omega_{k, 0} + \displaystyle \frac{\Omega_{m,0} }{a} + \Omega_{\Lambda,0} a^2 \right)}}} = 1
With \Omega_{k, 0} = 1 - \Omega_{m,0} - \Omega_{\Lambda,0}.
It would be nice to see graphically how the surface \mathcal{I}(\Omega_{m,0}, \Omega_{\Lambda,0}) behaves depending on different values of \Omega_{m,0} and \Omega_{\Lambda,0} (for example, between [0, 1]). Unfortunately I do not have the tools to do such graphics.