Are Parallel Circuits Affected When One Bulb Goes Out?

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SUMMARY

The discussion centers on the behavior of parallel circuits, specifically regarding light bulbs. When one bulb in a parallel circuit goes out, the remaining bulb does not increase in brightness due to the constant voltage across it, which remains at 110V. The current through the functioning bulb remains unchanged because the overall circuit's total current decreases, but the current in the active leg remains stable. This illustrates the principles of electrical resistance and current flow in parallel circuits.

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  • Knowledge of electrical resistance and equivalent resistance in parallel circuits
  • Familiarity with power ratings of electrical devices (e.g., 100W bulbs)
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iScience
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my living room light switch controls two lights. one of the light bulbs just went out.
since the switch controlled two bulbs, aren't they in parallel? so then why didn't the light bulb that is still on get any brighter?
 
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Why would you expect a bulb with a given wattage get brighter?
 
dlgoff said:
Why would you expect a bulb with a given wattage get brighter?

indeed.

consider that it still has the same voltage across it 110V 240V ( whatever in your country)

so say 100W globe, 110V what is the current flowing through it ?

2 x 100W globes in parallel with 110V across them, what is the current through each of them ?

3 100W globes in parallel with 110V across them, what is the current through each of them ?

when you have worked that out ... do you see where its leading ?

cheers
Dave
 
I thought the power rating tells you what the device was made for. regardless of what current and voltage you put across the device, the device has its inherent Z value, whether or not its dynamic (a function).if the light in parallel goes out, all the sudden there is a change in Z(eq). Remaining at the same brightness implies either...

1.) The circuit is not just a simple parallel circuit.

or..

2.) the light bulb has somehow increased its Z value.there is definitely an initial change in Z(eq); what i'd like to know is what happened such that the current remained the same?
 
so say 100W globe, 110V what is the current flowing through it ?

2 x 100W globes in parallel with 110V across them, what is the current through each of them ?

3 100W globes in parallel with 110V across them, what is the current through each of them ?

when you have worked that out ... do you see where its leading ?

$$I=\frac{P}{V}=\frac{V}{R_{eq}}=V(\frac{1}{R_1+R_2+...})$$

still dependent on the number of loads in parallel. i still don't get it
 
iScience said:
there is definitely an initial change in Z(eq); what i'd like to know is what happened such that the current remained the same?

why do you think current has remained the same?
 
because the second light bulb (one that's still on) didn't change in brightness
 
iScience said:
because the second light bulb (one that's still on) didn't change in brightness

right, the current in that leg of the parallel circuit has stayed the same. But the other leg now has zero current, so the total current in the light fixture must have dropped in half.
 
ohhh... i see .

okay thanks!
 

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