I would say that multiplication can be considered repeated addition, just like we can say an integral is just an anti-derivative. It's true that an integral is an anti-derivative, but it has properties that are far more reaching than just being an anti-derivative. So, just like it's okay to think of an integral as an anti-derivative, but not to force it upon it. Just like multiplication is thought of to be repeated addition, it isn't the only thing it does.
Let's take the integers as our set and look at how addition, and multiplication are different. Under group axioms, we need our set, when two elements are operated on, to be: closed, associative, have an identity, and have an inverse. So, looking at addition, we see that: It's closed, it's associative, it has an identity, which is 0, and it has an inverse, which would just be -a, for some element a.
Now let's look at multiplication as repeated addition. Well, since addition was closed, repeated addition can also be closed. It's associative, since addition was. The identity doesn't change, it's still 0, and the inverse also doesn't change, it's still going to be some -a.
Now let's look multiplication as not repeated addition. Well, it's closed under the integers, it is associative, it has an identity, which would be 1. Problem 1, in my eyes. The next one would be that multiplication has no inverses in the Integers! There is nothing I can multiply an integer by (other than 1) to get back my identity.
And that's where we can see that multiplication isn't actually repeated addition, because not only do I have different identity elements, but one of the operators gives me a group structure, but the other one isn't even a group at all! For those reason, I would say multiplication is *not* repeated addition, but merely a good way to think about it. But then again, it also depends on what you're considering as axioms.