Are These Probability Calculations Correct?

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P(\text{stop at first light signal}) = 0.4 = P(A)

P(\text{stop at second light signal}) = 0.5 = P(B)

P(\text{stop at least one of two signals}) = 0.6 = P(A \cup B)

Then P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.3

P( \text{first signal but not second}) = P(A \cap B') = 1-0.3 = 0.7

P(\text{exactly one signal}) = P(A \cup B) - P(A \cap B) = P(A \Delta B) = 0.3


Are these correct?
 
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They are; except can you explain P(1st but not 2nd) = 0.7?
 
yeah that's incorrect. It should be P(A \cap B') = P(A) - P(A \cap B) = 0.4-0.3 = 0.1
 
tronter said:
yeah that's incorrect. It should be P(A \cap B') = P(A) - P(A \cap B) = 0.4-0.3 = 0.1
Shouldn't it be P(A \cap B') = P(A) * (1-P(B))

Assuming there independent
 
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