I was watching a show the other night about the Large Hadron Collider, and I got to wondering how much force it would take to push two uranium nuclei right up against each other. I figured it would be on the order of a thousandth, maybe a millionth of a pound, which seems like a lot, considering how small an atomic nucleus is. Boy, was I surprised. IT'S NEARLY 2,000 LBS! Can that be correct? I assumed 92 protons per nucleus, each having a positive charge of 1.602x10^-19 coulombs. I assumed a distance between nuclear centers of 15 femtometers (15x10^-15 m). And I used Coulomb's Law for the force between charged objects. Since I was on a role, I then calculated how much force it would take to separate all the electrons in a copper penny from all the protons, assuming all the positive and negative charges are arranged as penny-sized disks that are 1.55 millimeters apart, which is the thickness of a penny according to Wikipedia. Of course it would be impossible to do this experimentally. But assuming two penny-sized disks separated by 1.55 mm, THE FORCE OF ATTRACTION EXCEEDS THE WEIGHT OF THE EARTH! That much force to separate the charges would, as I calculate it, would require an amount of energy on the order of two centuries of human energy use (at our current rate of ~13-trillion watts). I must be making an error. I assumed 3.5 grams for a copper penny, 100% copper, atomic number 29, and atomic weight 63.5. Used Coulomb's Law here also.