Are vectors independent of reference frames?

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Vectors are indeed independent of reference frames, but their components can change when the frame is rotated or transformed. The relationship between vectors in different frames involves a rotation tensor, which accounts for these changes in components. The equation X=R+Q.V' reflects this dependency, indicating that while the vector itself remains unchanged, its representation in different coordinate systems does not. In a mathematical context, the definition of a vector may vary, leading to different interpretations of transformation. Understanding these distinctions is crucial in both physics and mathematics when discussing vectors and their representations.
TonyEsposito
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Ok, this is the notation I am going to use in this thread: uppercase means vectors, while "[V]c" means coordinates of vector V in frame c.
I'm reading from a book: i have a reference frame "a" and a reference frame "b" rotated with respect to "a", the vector connecting the frames origin is R.
We are tracking a particle having radius vector X in frame a and X' in frame b, the book says that the relation connecting the two vector is:

X=R+Q.V'
where Q is the rotation tensor of the two frames...but arent vectors indipendent of frames? should not the relation be simply:

X=R+V'

and only when expressed in a coordinates Q comes into play?

[X]a=[R]a+Q.[V']b
[X]b=[R]b+Q^-1.[V']a
 
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TonyEsposito said:
but arent vectors indipendent of frames?
They are... But their components are not. If you rotate or stretch or shrink or deform your coordinate frame the components change which what those tensors are used for.
 
I agree, as long as the term "vector" is interpreted in the physics/tensor context. In a pure mathematical context, it is possible to call something a "vector" where it does not transform as a tensor would. (A mathematician might define something like (1,0) as a unit "vector" even though it does not transform at all.)
 

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