- #36
DODGEVIPER13
- 672
- 0
Integrate from 1 to 0 of x^2 dx and I get -1/3 evaluate the second integral from 0 to 1 of 2x^5 dx and get 1/3 added together I get 0 which is not right?
DODGEVIPER13 said:Or is it just one integral once I do the substitution from 1 to 0 of x^2+2x^5 which would be -2/3
DODGEVIPER13 said:Ok man so do you suggest I ask separate questions for the rest also I will give a thanks? I was wondering if I add one thanks does it count for all the posts.
DODGEVIPER13 said:well nvm that does not sum to 180 degrees but I think I may have solved it I got 76.86,57.31, and 45.81 is that correct?
DODGEVIPER13 said:sorry one final check on 1.2 the perpendicular part, I already have the parallel part. I found alpha= 4 and beta=1 is this right?
DODGEVIPER13 said:If their dot product equals zero then they are perpendicular which my numbers seem to pass. As long as I'm doing the dot product right which I am pretty sure I am multiplying like values together and adding them.
DODGEVIPER13 said:A=AlphaUx+3Uy-2Uz and B=4Ux+betaUy+8Uz then by observation I noticed if I plugged 1 in for alpha then when I multiplied 4Ux and 1 Ux I would get 4. I then saw that is I plugged 4 in for beta then when 3Uy and 4Uy multiplied I would get 12. These added together gave me 16 and when -2Uz and 8Uz I get -16 when added together I get 0 which I assumed was right but I'm guessing its not.
DODGEVIPER13 said:Ok I got something wonky trying to do the cross product of that I can't upload it until around 1 so ill do it then but typically when you have 2 unknowns I would need a second equation correct? They must then both multiply times the constants to form the 0 maybe?
DODGEVIPER13 said:ah makes sense so this obviously isn't the only solution but nonetheless one that will be correct right?