DryRun
Gold Member
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Homework Statement
http://s2.ipicture.ru/uploads/20120107/67Ag24Qb.jpg
The attempt at a solution
So, i plotted the graphs of the circle and the curve:
http://s2.ipicture.ru/uploads/20120107/x32KTV6y.jpg
The shaded area is what i need to find. My plan to solve this problem is to find the area with respect to the y-axis of the curve minus the right-half of the circle.
Area of left-side of curve:
For y fixed, x varies from x=0 to x=4-y^2
y varies from y=-2 to y=2
I did double integral with the limits above, w.r.t. dxdy and got 32/3
Area of right-half of circle:
For y fixed, x varies from x=0 to x=√(4-y^2)
y varies from y=-2 to y=2
Again, I've done double integral and ended up with 2pi
I don't know which of these 2 integrals are wrong, as the difference doesn't give me the correct answer, although it's close.
http://s2.ipicture.ru/uploads/20120107/67Ag24Qb.jpg
The attempt at a solution
So, i plotted the graphs of the circle and the curve:
http://s2.ipicture.ru/uploads/20120107/x32KTV6y.jpg
The shaded area is what i need to find. My plan to solve this problem is to find the area with respect to the y-axis of the curve minus the right-half of the circle.
Area of left-side of curve:
For y fixed, x varies from x=0 to x=4-y^2
y varies from y=-2 to y=2
I did double integral with the limits above, w.r.t. dxdy and got 32/3
Area of right-half of circle:
For y fixed, x varies from x=0 to x=√(4-y^2)
y varies from y=-2 to y=2
Again, I've done double integral and ended up with 2pi
I don't know which of these 2 integrals are wrong, as the difference doesn't give me the correct answer, although it's close.
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