Area of triangle by integrals (is this right?)

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Homework Help Overview

The problem involves using integrals to calculate the area of a triangle defined by the vertices (0,5), (-2,-2), and (2,2).

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the method of integrating to find the area, with one questioning a specific integral transformation. Others reflect on potential errors in their calculations and seek confirmation of their results.

Discussion Status

The discussion includes attempts to verify calculations and methods, with some participants expressing uncertainty about their results. There is acknowledgment of a corrected approach, and one participant confirms their area calculation as correct.

Contextual Notes

Participants are navigating through potential miscalculations and clarifying their understanding of the integral setup. The original poster seeks validation of their method before proceeding further.

silicon_hobo
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[SOLVED] area of triangle by integrals (is this right?)

Homework Statement


Use integrals to find the area of a triangle with vertices (0,5),(-2,-2),(2,2).

Homework Equations



The Attempt at a Solution


I think I've got it. I'm just looking for some confirmation of my method before I move on.
Thanks for your time. Cheers.

http://www.mcp-server.com/~lush/shillmud/quest3.jpg

P.S. How do I add a [Solved] to the title?
 
Last edited:
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How are you getting e.g. integral of 5x/2+5 to be 5x^2/4+5x^2/2??
 
Ooops. Thanks for pointing that out Dick. I found the dx of 5x instead of the dx of 5 which interestingly seems not to have affected my answer. I guess you can see why I'm using the forum. Everything should be in order now. Cheers.
 
silicon_hobo said:
Ooops. Thanks for pointing that out Dick. I found the dx of 5x instead of the dx of 5 which interestingly seems not to have affected my answer. I guess you can see why I'm using the forum. Everything should be in order now. Cheers.

If you are still getting 20 for the area, I can't agree with that. Double check again.
 
Okay, I went through again and got A=10. When putting in values for x to solve I sub the rightmost value from the top of integral sign and then subtract from that the same antiderivative with the leftmost x value (top of the integral sign). This is correct? Thanks!
 
Yes, A=10 works.
 
Thanks Dick. Heron's method confirms it. Now how do I mark this one [SOLVED] ?
 
Under Thread Tools, at the top, isn't there a "Mark this thread as solved"?
 

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