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Area of triangle by integrals (is this right?)

  1. Mar 10, 2008 #1
    [SOLVED] area of triangle by integrals (is this right?)

    1. The problem statement, all variables and given/known data
    Use integrals to find the area of a triangle with vertices (0,5),(-2,-2),(2,2).

    2. Relevant equations

    3. The attempt at a solution
    I think I've got it. I'm just looking for some confirmation of my method before I move on.
    Thanks for your time. Cheers.

    [​IMG]

    P.S. How do I add a [Solved] to the title?
     
    Last edited: Mar 10, 2008
  2. jcsd
  3. Mar 10, 2008 #2

    Dick

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    How are you getting e.g. integral of 5x/2+5 to be 5x^2/4+5x^2/2??
     
  4. Mar 10, 2008 #3
    Ooops. Thanks for pointing that out Dick. I found the dx of 5x instead of the dx of 5 which interestingly seems not to have affected my answer. I guess you can see why I'm using the forum. Everything should be in order now. Cheers.
     
  5. Mar 10, 2008 #4

    Dick

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    If you are still getting 20 for the area, I can't agree with that. Double check again.
     
  6. Mar 10, 2008 #5
    Okay, I went through again and got A=10. When putting in values for x to solve I sub the rightmost value from the top of integral sign and then subtract from that the same antiderivative with the leftmost x value (top of the integral sign). This is correct? Thanks!
     
  7. Mar 10, 2008 #6

    Dick

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    Yes, A=10 works.
     
  8. Mar 10, 2008 #7
    Thanks Dick. Heron's method confirms it. Now how do I mark this one [SOLVED] ?
     
  9. Mar 10, 2008 #8

    Dick

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    Under Thread Tools, at the top, isn't there a "Mark this thread as solved"?
     
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