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## Homework Statement

I'm not sure how to proceed here. The first one asks me to find the area of a surface obtained by rotating the curve [tex]y = cos(x), 0 \leq x \leq\ \frac{\pi}{3}[/tex]

The second one asks to Solve: [tex]\frac{dy}{dt} = \frac{ty+3t}{t^2+1}\ y(2)=2[/tex]

## Homework Equations

## The Attempt at a Solution

http://www.mcp-server.com/~lush/shillmud/int3.4.JPG

I've tried a bunch of different substitutions but I always stall on the integration.

http://www.mcp-server.com/~lush/shillmud/int3.7.JPG

I'm not sure how to satisfy the condition y(2) = 2. Thank you again for your help.

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