Difficult integral by sub., parts & table

Click For Summary

Homework Help Overview

The discussion revolves around the integral \(\int xe^{2x^2} \cos(3x^2) \, dx\), which the original poster describes as particularly challenging. The problem involves techniques such as substitution and potentially integration by parts.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore substitution with \(u = x^2\) and discuss the transformation of the integral. There are references to using a known formula for integrals involving exponential and trigonometric functions. Some participants express uncertainty about the correctness of their approaches and results.

Discussion Status

There are various attempts to solve the integral, with some participants providing their results and checking them against computational tools. However, there is no explicit consensus on the correctness of the solutions presented, and the discussion remains open with participants seeking clarification and further input.

Contextual Notes

Some participants question the simplification of results and the accuracy of their methods. Additionally, there are side discussions about how to share scanned work on the forum, indicating a focus on the presentation of solutions rather than the solutions themselves.

silicon_hobo
Messages
59
Reaction score
0

Homework Statement


\int xe^{2x^2} cos(3x^2) dx
This is the hardest integral I've attempted so far. I've come up with an answer that fits a table in my book but I'm not sure if I arrived there correctly. Thanks for reading!


Homework Equations


\int e^{au} cos\ bu\ du\ = \frac{e^{au}}{a^2+b^2}(a\ cos\ bu\ + b\ sin\ bu)+C


The Attempt at a Solution


http://www.mcp-server.com/~lush/shillmud/int2.7.JPG
http://www.mcp-server.com/~lush/shillmud/int2.72.JPG
 
Physics news on Phys.org
substitute:

u=x^2

du=2x dx

I=\int xe^{2x^2}\cos(3x^2){\rm dx}\,=\, {1\over 2} \int e^{2u}\cos(3u) {\rm du}

I have done some shortcut here, with use of the formula, your number two:

I={1\over 26} e^{2u} (2 \cos(3u)\,+\,3\sin(3u))\,+\,C

I={1\over 26} e^{2x^2} (2 \cos(3x^2)\,+\,3\sin(3x^2))\,+\,C

this is the same as integrator...

http://integrals.wolfram.com/

check it out
 
Here's the solution, I didn't simplify it any more like I should have, but I hope you understand the basic process. I checked my answer with CAS and it's correct, so don't worry about that.
http://img411.imageshack.us/img411/5615/file0001su6.jpg
 
Last edited by a moderator:
How do you submit scanned work onto here?
Thanks
 
SavvyAA3 said:
How do you submit scanned work onto here?
Thanks

Assuming the scanned image is in a format the forum recognises, jpeg,mpeg and so on either click on the icon in yellow with a black mountain or two and a black sun, visible in the new reply or go advanced: edit windows, not quick post. Or type [noparse]*url [/noparse] around the files url.

To get a url for an image stored on your hard drive you will need to upload it to a web host facility such as photobucket or freewebs. And then cut and paste the url. If not then use the paper clip to attach files directly from your hard drive to the forum. With this option there will be a delay while the forum scans the file for viruses, but any format that is listed there from jpeg to gif are acceptable.
 
Last edited by a moderator:
Thanks a lot!
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K