Area problem, involving quadratic functions

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SUMMARY

The discussion focuses on optimizing the area of a rectangular fenced enclosure divided into five equal pens, using a total of 120 meters of fencing material. Participants emphasize the importance of defining variables for the dimensions of the enclosure, specifically x and y, to express the total area A(x,y) and the fencing constraint F(x,y)=120. By establishing these relationships, users can apply techniques such as completing the square and understanding parabolas to maximize the area. The key takeaway is to visualize different designs and derive equations that relate the area and fencing length.

PREREQUISITES
  • Understanding of quadratic functions and their properties
  • Knowledge of completing the square technique
  • Familiarity with the concept of maximum and minimum values in calculus
  • Ability to define and manipulate algebraic equations
NEXT STEPS
  • Learn how to derive equations for area and perimeter in geometric optimization problems
  • Study the method of Lagrange multipliers for constrained optimization
  • Explore graphical methods for visualizing quadratic functions and their maxima
  • Practice solving similar problems involving fencing and area maximization
USEFUL FOR

Students studying calculus, mathematics educators, and anyone involved in optimization problems related to geometry and area maximization.

bonnieerika
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Hi, I don't understand what this question is asking and I have idea how to do it.. any help is very much appreciated! I understand how to complete the square, parabolas and such and the concept of maximum and minimum, I just don't understand this question.

A Cattle farmer wants to build a rectangular fenced enclosure divided into 5 rectangular pens. Each pen has equal area.

[diagram shows picture of 5 rectangular pens side by side, all of them are the same size]

A total length of 120 m of fencing material is available. Find the overall dimensions of the enclosure that will make the total area a maximum.
 
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bonnieerika said:
Hi, I don't understand what this question is asking and I have idea how to do it.. any help is very much appreciated! I understand how to complete the square, parabolas and such and the concept of maximum and minimum, I just don't understand this question.

A Cattle farmer wants to build a rectangular fenced enclosure divided into 5 rectangular pens. Each pen has equal area.

[diagram shows picture of 5 rectangular pens side by side, all of them are the same size]

A total length of 120 m of fencing material is available. Find the overall dimensions of the enclosure that will make the total area a maximum.

Start by drawing out the enclosure and labelling the dimensions of a single rectangle with x and y (or you can give the entire enclosure those variables if you wish).
Now, what is the area equal to in terms of x and y? i.e. Find A(x,y).
What about the length of fencing in terms of x and y? We also know that the fencing is 120m so you'll have an equation in two variables given by F(x,y)=120.
 
bonnieerika said:
Hi, I don't understand what this question is asking and I have idea how to do it.. any help is very much appreciated! I understand how to complete the square, parabolas and such and the concept of maximum and minimum, I just don't understand this question.

A Cattle farmer wants to build a rectangular fenced enclosure divided into 5 rectangular pens. Each pen has equal area.

[diagram shows picture of 5 rectangular pens side by side, all of them are the same size]

A total length of 120 m of fencing material is available. Find the overall dimensions of the enclosure that will make the total area a maximum.

You really do need to make an effort before asking for help, but here are some hints.

Try drawing a couple of different "designs", each using a total of 120 of fencing and having 5 equal rectangular pens. Do you see how you can have different areas?

Now start defining some "variables" connected with your designs, and try to express two things in terms of them: (1) the total area enclosed; and (2) the total length of fencing used. Equating (2) to 120 m will give a relationship between your variables, and that will help you with the task of maximizing (1).
 

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