Arithmetic Progression Problem

AI Thread Summary
The discussion revolves around solving an arithmetic progression problem where the sum of the first 7 terms is 28 and the sum of the first 15 terms is 90. The user derives the common difference (d) as 7.75 and the first term (a) as -18.5 using the equations for the sums of the terms. However, there is confusion regarding the application of the formulas, as the user initially misinterprets the sums as individual terms rather than cumulative sums. Ultimately, the correct formula for the sum of n terms is confirmed, emphasizing the need to use Sn = (n/2)[2a+(n-1)d]. The discussion highlights the importance of accurately applying mathematical formulas in problem-solving.
z.js
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Homework Statement


If the sum of the first 7 terms of an arithmetic progression is 28 and the sum of the first 15 terms is 90, find the sum of n terms.:eek:


Homework Equations


Sn = 0.5n[2a+(n-1)d]
a is the first term and d is the common difference. n is the number of terms.
nth term = a + (n-1)d


The Attempt at a Solution


(here goes :rolleyes:)
(1)...a + 6d = 28
(2)...a + 14d = 90
(2)-(1)...8d = 62
...d = 7.75 (ok :cool:)
(1)...a + 6(7.75) = 28
.....a = -18.5 (yea! :biggrin:)
(drumrollllllllllll)
Sn = 0.5n(-37 + (n-1)7.75)
= -18.5n +n(n-1)3.875
= n[3.875(n-1) - 18.5] :approve:
...:mad: now what? the answer was n/4(n + 9)
 
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z.js said:

Homework Statement


If the sum of the first 7 terms of an arithmetic progression is 28 and the sum of the first 15 terms is 90, find the sum of n terms.:eek:

Homework Equations


Sn = 0.5n[2a+(n-1)d]
a is the first term and d is the common difference. n is the number of terms.
nth term = a + (n-1)d

The Attempt at a Solution


(here goes :rolleyes:)
(1)...a + 6d = 28
(2)...a + 14d = 90
(2)-(1)...8d = 62
...d = 7.75 (ok :cool:)
(1)...a + 6(7.75) = 28
.....a = -18.5 (yea! :biggrin:)
(drumrollllllllllll)
Sn = 0.5n(-37 + (n-1)7.75)
= -18.5n +n(n-1)3.875
= n[3.875(n-1) - 18.5] :approve:
...:mad: now what? the answer was n/4(n + 9)

You have used formula of the nth term instead of using that of sum of n terms .28 is not the 7th term .Instead it is the sum of first 7 terms .Similarly with 90 being the sum of first 15 terms.

Use Sn = (n/2)[2a+(n-1)d]
 
Last edited:
ahh! I forgot! thanks
 
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