Arrange Cows in Pens: 1000 Cows & 10 Pens

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To arrange 1000 cows in 10 pens such that any number of cows from 1 to 1000 can be obtained, the cows should be distributed in powers of two: 1, 2, 4, 8, 16, 32, 64, 128, 256, with the remaining 489 cows in the last pen. For numbers less than 489, open the first nine pens based on their binary representation. For numbers greater than 489, open the 489 pen and then select additional pens according to binary representation. The discussion also touches on the historical context of weights and measures, questioning whether the choice of 16 ounces per pound was intentional due to its binary-like structure. The arrangement effectively utilizes binary notation for efficient distribution.
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Given 1000 cows and 10 pens, you want to arrange the cows in the pens such that any number of cows from 1 to 1000 can be obtained by opening certain pens and taking all the cows in those pens. How do you arrange the cows in the pens?
 
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This is equivalent to finding a binary representation for a number. Arrange the cows like this

1, 2, 4, 8, 16, 32, 64, 128, 256 and the remaining 489

If the given number is smaller than 489, then simply open the first 9 pens according to the binary representation of the number. If the number is larger then open the 489 pen, and open the remaining again in binary.
 
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Concerning the solution to the riddle. The use of the binary notation is interesting.When I was younger and we weighed in lbs and ozs we had a set of scales with weights that stacked neatly by the side of the scales The weights were 1,2,4,8 and 1 lb =16oz then the same with lb weights stopping at7lb , I think.
My mother could weigh any weight with these. Question. Was the 16 ounces =One pound deliberately chosen for the given reason or was it accidental??
 
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