Asap help please~electric fields from continuous charge distribution?

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SUMMARY

The discussion centers on calculating the x-component of the electric field at point P due to a uniformly charged nonconducting rod of length 2a with total charge Q. The user derived the expression for the electric field using integration, resulting in Ex = [kQ/(2a^2*sqrt(5))]*{sqrt(5) -1}. The calculation involves substituting variables and applying limits to the integral, confirming the correctness of the approach. The user seeks validation of their solution and expresses a willingness to learn further.

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Hello guys,

I tried to figure this out and I got my answer. I just want to check it. So would you guys please help me with it? Thank you!
Here is the question:
A nonconducting rod of length 2a has a charge Q uniformly distributed along it. Find the expression for x-component of the electric field at point P(a distance above one of the ends of the rod)

my answer:

Ex = Integral from x = -2a to 0 of [(k*Q/2a)*xdx/ (x^2+a^2)^(3/s2)]
set x^2+a^2 = y
x*dx = dy/2 also x = -2a y = 5a^2
x = 0 y =a^2

Ex = -2*(k*Q/4a)[1/sq rt(y)] within limits of y = 5a^2 to y = a^2]
= - (kQ/2a)*[1/sq rt(5a^2) – 1/sq rt(a^2)] = -(kQ/2a^2)[1/sq rt(5) -1]
= [kQ/(2a^2*sq rt(5))]*{sq rt(5) -1]

is that correct?
Thank you and I am willing to learn from you ;)
 
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