Astro, flux & energy

  • Thread starter Qyzren
  • Start date
  • #1
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The neutrino flux from supernova 1987A was estimated to be 1.3e14 m^-2 at the Earth. SN 1987A occured in the Large Magellanic cloud, which is located at a distance of 50 kpc. If the average energy per neutrino was 4.2 MeV, estimate the amount of energy released in the form of neutrinos during the supernova explosion

Homework Equations


electron volt = 1.602e-19 J
pc = 3.086e16 m

The Attempt at a Solution


Answer says: 2.6e45 J

I can't seem to get the answer... :(
any help will be appreciated :)
i was thinking since flux falls off ~ 1/d².
so i tried E = flux *d²*avg energy of neutrino
1.3e14*(50000*3.086e16)²*4.2e6*1.602e-19
=3.258e44 J.
So i'm off by more than a factor of 10... :(
What am i doing wrong??
 

Answers and Replies

  • #2
malawi_glenn
Science Advisor
Homework Helper
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the area of a spehere is [tex] 4 \pi r^2 [/tex]

So you should multiply with 4pi = 12,.. =)

also check the numericals, 1.3e14*(50000*3.086e16)²*4.2e6*1.602e-19 = 2.08*10^44 J
 
  • #3
44
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oh!! Thank you
(yeh i think i typed something wrong in the calculator before).
 
Last edited:

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