Astronomic gravitation problems

  • Thread starter Thread starter philadelphia
  • Start date Start date
  • Tags Tags
    Gravitation
AI Thread Summary
The discussion addresses three key problems related to gravitational physics. First, participants explore calculating the orbital period of the International Space Station using its velocity and Earth's mass and radius. Second, they analyze the altitude required for a communications satellite above Mars to maintain a geostationary position, considering the length of a Martian day. Lastly, the conversation shifts to finding the Lagrange Point between the Sun and Jupiter, with participants discussing relevant equations and the relationship between gravitational forces and orbital mechanics. The Lagrange Point is identified as being associated with the Trojan Asteroids, located at the L4/L5 points.
philadelphia
Messages
7
Reaction score
0
1. If the INternational space station has an orbital velocity of 9,000 m/s. find the time (in minutes) it takes to make one complete orbit.

Relevant equations
F = mv2/ R = m4[pi]2R / T2

The attempt at a solution
Is this the way to solve for T?
Do I use Earth mass and Earth R b/c that all the question says?


2. A martian day is 1.03 Earth days. At what altitude above Mars should a communications satelite be placed such that it always stay over the same spot above the surface of Mars (answer in units of miles. 1000m = 0.62 miles

Relevant equations
F = ma = m4[pi]2R / T2
a= GM/R2

The attempt at a solution
I know how to solve the problem but what kinda threw me off are the martian days given...
Is T 354.36 days that is 365/1.03
If it is, can i find "a" after the "m" cancel, than solve for R which is (mar's radius + Mars altitude)


3. find the lagrange Point between the sun and Jupiter. In between what two planets will you find this point?

Jupiter:
mass: 1.9x1027 kg

Sun:
mass: 1.99x1030

distance betwwen sun and Jupiter: 778x106 km

Relevant equations
Im really not sure what is lagrange point equation, is it... GMsunmjupiter/ r
r is the distance of Jupiter- sun ?
 
Physics news on Phys.org
You have the velocity and and hence you have

mv²/r = Gravitational force = GMm/r²

This yields v² = GM/r

What you don't know from that equation is r. But you want to calculate it, because v/r = ω

and ω = 2πf = 2π/T or

T = 2π/ω = 2πr/v
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top