Astronomy: Explaining Why Stars on Top Left of Main Sequence Spend Less Time

  • Thread starter Thread starter vanilla5085
  • Start date Start date
  • Tags Tags
    Astronomy Stars
AI Thread Summary
Stars on the top left of the main sequence, typically more massive and hotter, have higher rates of nuclear fusion, leading to faster consumption of their hydrogen fuel. In contrast, stars on the lower right are less massive and cooler, allowing them to sustain hydrogen fusion for a longer duration. The difference in mass and temperature directly influences their lifespans on the main sequence, with more massive stars having significantly shorter lifetimes. This phenomenon is a fundamental aspect of stellar evolution and is well-documented in astrophysics. Understanding these differences is crucial for studying the life cycles of stars.
vanilla5085
Messages
1
Reaction score
0
Hi, I was just wondering if anyone could help me with this question. I couldn't find anything on the internet.

Q12 Explain why a star on the top left of the main sequence will spend much less time on the main sequence than another star on the lower right
 
Physics news on Phys.org
Nothing at all? How hard did you look?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top