TEFLing
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TEFLing said:...
( Tcore / Tsurface ) ~ M/R2
...
From VT,
Tcore ~ M/R
So
Tsurface ~ R
I think that is qualitatively correct, and maybe even semi quantitatively so
TEFLing said:...
( Tcore / Tsurface ) ~ M/R2
...
Yes, that logic works for me. It overestimates a little how much the surface T varies, but that's not surprising given that the opacity is assumed constant and convection is neglected. If anyone is just now coming into the thread, notice we are strictly talking about ideal-gas-pressure stars that transport energy by radiative diffusion, so these expressions do not apply to giants or white dwarfs, or even main-sequence stars at very low or very high mass. But it should all give reasonably semi-quantitative results for main-sequence stars between about 0.5 and 50 solar masses.TEFLing said:From VT,
Tcore ~ M/R
So
Tsurface ~ R
I think that is qualitatively correct, and maybe even semi quantitatively so
Only for white dwarfs, which are the stellar equivalent of a multiple-particle Pauli-excluded Bohr atom.TEFLing said:In QM, you can calculate the Bohr radius of H by writing the equation for electron energy, and differentiating to find the dx = h/dp which minimizes the total energy
Does something similar work for stars as well?
U ~ -2/5 GM^2/R
K ~ -1/2 U
?
Yes, true!TEFLing said:Maybe for NS also?
The expression on the left is only true at a surface-- not in an optically thick interior. In the interior, T4 has the meaning of an energy density per volume, not a flux per unit area. To connect it with flux, you need to know the optical depth, and divide your expression on the left by the optical depth to that r. You end up with a T4 gradient (in tau space rather than real space) that acts a lot like a heat conduction, where the gradient in T4 gives you the flux, not T4 itself. That's the radiative diffusion physics that gave L ~ R4T4/M, because optical depth goes like M/R2 for a characteristic total value.Outside the stellar core, shouldn't L(r) remain constant? Otherwise energy would be accumulating or draining from material in some spherical shell
If so, then
4pi r^2 T(r)^4 = L(R) = constant
T ~ r^-0.5
That works if you make each shell one photon mean-free-path thick. Then you get the same thing as above, it gives a diffusion process.TEFLing said:If I try to consider concentric spherical shells, each radiating outwards and inwards, balanced by inwards from the next shell out plus outwards from the next shell in...
Then it seems like dL/dr = constant
E.g. Surface shell radiates one unit of power out and another in...
The next shell inwards radiates two units outwards ( replenishing the surface shell ) and two units inwards...
The third shell radiates three units...
And so on
Ken G said:That works if you make each shell one photon mean-free-path thick. Then you get the same thing as above, it gives a diffusion process.
trying to upload figure from Wolfram Alpha websiteTEFLing said:Oh I understand now
dL/d(tau) = constant
If you ignore the surface luminosity as small compared to the core luminosity...
Then
L(r) = L0 (1 - (r/R))
T(r) ~ (1/r^0.5) (1 - (r/R))^0.25
That situation does not have an increasing L, it has a nonzero L (it has L=1).TEFLing said:L can increase linearly inwards, and still keep every shell in equilibrium
Shell two radiates two units of power outward and inwards (-4), but gets one from above and three from below (+4)
L increases inwards but the star is in equilibrium
Total energy, or energy in form of photons?Ken G said:The expression on the left is only true at a surface-- not in an optically thick interior. In the interior, T4 has the meaning of an energy density per volume, not a flux per unit area.
Ken G said:To connect it with flux, you need to know the optical depth, and divide your expression on the left by the optical depth to that r. You end up with a T4 gradient (in tau space rather than real space) that acts a lot like a heat conduction, where the gradient in T4 gives you the flux, not T4 itself.
Photons only.snorkack said:Total energy, or energy in form of photons?
Yes. So that's why the cooler interiors of protostars must carry their high luminosities convectively-- effectively lousy radiative heat conductivity, despite the low optical depths. But as they contract and T rises, eventually their radiative heat conductivity rises to the point that radiation can transport their luminosity throughout most of the star, and that's when L saturates at its ~ M3 value.So, if heat conduction is in a narrow range of temperature, then the energy flux
dE/dt*dS=c1*(dT/dr)
If the relevant gradient is T4 then its derivative
d(T4)=4*T3*dT
and then
dE/dt*dS=c2*4*T3*(dT/dr)
so it matches
c1=c2*4*T3
Thus, conductivity proportional to the cube of the temperature.
Correct?
Is there a radius effect also?Ken G said:Photons only.
Yes. So that's why the cooler interiors of protostars must carry their high luminosities convectively-- effectively lousy radiative heat conductivity, despite the low optical depths. But as they contract and T rises, eventually their radiative heat conductivity rises to the point that radiation can transport their luminosity throughout most of the star, and that's when L saturates at its ~ M3 value.
I want to dispute thatKen G said:That situation does not have an increasing L, it has a nonzero L (it has L=1).
Shell 1. 2. 3.
=====
Losses -1-1. -2-2. -3-3
Gains +2. +1+3. +2+4
--------
Net. 0. 0. 0
The energy per time isn't R2 T4, that assumes time ~ R. Actually it's diffusive, so time ~ R/v, where v is not c, it is c/tau, for tau the optical depth. Since tau ~ M/R2, it actually works the other way-- larger R allows light to escape faster. So that's where the L ~ R4 T4 / M comes from.TEFLing said:Is there a radius effect also?
Cooler stars tend to be smaller
And total power transport = energy per time ~ r^2 T^4
I thought that was what I was sayingKen G said:...- larger R allows light to escape faster..
The problem with your scenario is not that it isn't in equilibrium, it's that it has a constant luminosity of L=1 everywhere, yet you said it had a radial gradient in L. I'm sure you'll see this-- if L increased between shells, energy could not be conserved, just as a flow of water has to go somewhere. What is increasing inwards is not L, it is the energy density T4, and that's completely correct-- your scenario is just what is happening, but it's constant L.TEFLing said:I want to dispute that
In an idealized plane-parallel geometry, then zero second derivative means it is time steady diffusion, but there is still diffusion. The spherical symmetry changes things a bit.TEFLing said:I thought that was what I was saying
I guess I'm confused
A diffusion equation with no net diffusion would imply a zero second derivative, yes?
Kramers type opacity can certainly enter, especially for cooler stars. For hotter stars, electron scattering is at least close to dominant, if not completely dominant. So no doubt, assuming constant opacity is a bit of a stretch, but it's simple. There is no general expression, because electron scattering has no T dependence if H is ionized, Kramers opacity has a steeply dropping dependence with T, and H-minus opacity, important in the envelopes of very cool stars, actually rises with T at low T because you need some free electrons to make it work. So the opacity is all over the map, and you'd be totally wrong using electron scattering for stars less massive than the Sun, but you can get order-unity kinds of results for most of the main sequence. It's definitely the weakest assumption, some advanced authors try to include some opacity effects but there are subjective choices in the tradeoffs between complexity and accuracy.TEFLing said:http://en.wikipedia.org/wiki/Kramers'_opacity_law
Doesn't free free scattering dominate electron scattering given the large coefficients?
OK, then all is fine. Note that in standard lexicon, "transported through luminosity" is just "luminosity", and "shell luminosity" is just energy density times surface area, with the appropriate constant. But these are just the ways the words are normally used, when one is deep in the interior of the star it's pretty arbitrary what we might want to call the luminosity, and I agree with you that yours is a useful scenario for understanding how diffusion works.TEFLing said:I think I need to clarify vocabulary terms
I want one term for 'shell luminosity ' = 4pi r2 T4
Which is what you would see if you could magically excavate the stellar envelope down to that radius
And I want another word for Transported through luminosity ' which is the net diffusion of energy outwards...
And which is constant outside the core like you said for the energy conservation reason rationale you stated
There is indeed some latitude in what you do if you are not exactly solving the equations of stellar structure, giving the basic explanation for L a kind of subjective character. Personally, I'm not in favor of using the core and surface T as though they were the same thing, because they are set by very different physical processes. The core T is set by the need to self-regulate fusion to replace the heat that is diffusing out, and the surface T is set by the need for the blackbody emission at the surface to match that luminosity, so the former is fusion physics and the latter is Stefan-Boltzmann physics, and there is no reason the two should be the same or even proportional. So I wouldn't use L ~ R2 T4 for anything but a way to infer the surface T. Also, if you use diffusion physics to get L, you never need L ~ M2 / R3 Tn, you can just use L ~ R4 T4 / M from diffusion with constant opacity (or modify that for some other opacity like Kramers, but it won't be more accurate), and T ~ M/R from VT, and get L without even saying whether fusion is happening or not. However, if you want to get T in the core, and R, and then T at the surface, you would need to do what you are doing, since then you do need to know that fusion is happening.TEFLing said:L ~ M2 / R3 Tn
L ~ R2 T4
Those are the scaling relations I was looking for
They capture the general gist of the balance between core fusion and surface luminosity
And they give informatively useful and accurate results
Precise details are much more complicated