Astrophysics Problem - Protons Collision Temperature at Washington U

  • Thread starter Thread starter Tloh
  • Start date Start date
  • Tags Tags
    Astrophysics
AI Thread Summary
To determine the temperature required for two protons to collide, one must consider the Coulomb barrier and the velocities of the protons, which are ten times the root mean square (rms) velocity from the Maxwell-Boltzmann distribution. The discussion emphasizes calculating the energy needed for protons to overcome this barrier, using the Coulomb potential and the radius of a proton. By finding the required velocity and relating it to the rms velocity, one can derive the corresponding temperature. The approach is logical, but the complexity of the problem raises doubts about its correctness. Ultimately, the solution hinges on accurately applying these physical principles to find the necessary temperature.
Tloh
Messages
4
Reaction score
0
This is from Physics 312 Astrophysics at Washington University.

Question:

What temperature would be required for two protons to collide if quantum mechanical tunneling is neglected? Assume that nuclei having velocities ten times the root mean square (rms) value for the Maxwell-Boltzmann distribution can overcome the Coulomb barrier. Compare your answer with the estimated central temperature of the Sun.


My Rational:

I am stuck because I keep running in circles with this question. It asks to provide the temperature required for two protons to collide. Alright, good so far. Then it says that nuclei having velocities 10 times the rms will colide. Aren't these two statements in a loop? ie. the temperature controls the Maxwell-Boltzmann distribution and thus the rms and thus the 10rms and yet it is telling us that protons simply over the 10rms will collide. So, let's say the temperature is extremely low, the rms will be low and the 10rms will be low, but there will be a 10rms that exists... Any thoughts?
 
Physics news on Phys.org
The way that I read the question is this:

Find the temperature such that protons having ten times the rms velocity predicted by the Maxwell-Boltzmann distribution can overcome the Coulomb potential barrier and collide.
 
Found this website that could help you out:

http://www.answers.com/topic/maxwell-boltzmann-distribution

The way I understand the problem is that you should write down the Coulumb potential for 2 protons, and then plug in the radius of a proton to calculate the energy required for 2 protons to come in contact. Then you can use this energy to figure out the velocity of the proton. When you have the velocity, you divide it by 10 to get the root mean squeare velocity. Then using the link above you can find the equation that relates the rms velocity to the temperature in M-B distribution. Then you just solve the equation.

Makes sense to me, but that's no guarantee it's rigth :/
 
Borxter said:
Found this website that could help you out:

http://www.answers.com/topic/maxwell-boltzmann-distribution

The way I understand the problem is that you should write down the Coulumb potential for 2 protons, and then plug in the radius of a proton to calculate the energy required for 2 protons to come in contact. Then you can use this energy to figure out the velocity of the proton. When you have the velocity, you divide it by 10 to get the root mean squeare velocity. Then using the link above you can find the equation that relates the rms velocity to the temperature in M-B distribution. Then you just solve the equation.

Makes sense to me, but that's no guarantee it's rigth :/

thanks :), makes sense
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
1
Views
3K
Replies
3
Views
1K
Replies
2
Views
3K
Replies
5
Views
3K
Replies
1
Views
2K
Replies
5
Views
4K
Replies
19
Views
5K
Back
Top