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The first-order differential equation
y' +(ex^2+1+1/x^2)y=0, with boudary value y(1) =1
Using, asymptotic mathcing to study the behaviour of the sltion as e tends to +0, when x is not too large, the term ex^2 is negligible so an approximate equation for y is
y'_L +(1+1/x^2)y_L=0.
When x is large, [ tex ]ex^2 [ /tex ] is not negligible but 1/x^2 is. Therefore, an approximate equation valid as x tends to infinity is y'_R +(ex^2+1)y_R=0.
I think that te upper edge of the left region would be the largest value of x for which ex^2 is still small compared with 1. This would suggest that the left region consists of those x for which x<<e^-(1/2) as e tends to +0. But actually the region of validity of the left solution is e^(-1/3) (e tends to +0)...Can anyone explain this to me??
Sams as the right region...Please kindly help
y' +(ex^2+1+1/x^2)y=0, with boudary value y(1) =1
Using, asymptotic mathcing to study the behaviour of the sltion as e tends to +0, when x is not too large, the term ex^2 is negligible so an approximate equation for y is
y'_L +(1+1/x^2)y_L=0.
When x is large, [ tex ]ex^2 [ /tex ] is not negligible but 1/x^2 is. Therefore, an approximate equation valid as x tends to infinity is y'_R +(ex^2+1)y_R=0.
I think that te upper edge of the left region would be the largest value of x for which ex^2 is still small compared with 1. This would suggest that the left region consists of those x for which x<<e^-(1/2) as e tends to +0. But actually the region of validity of the left solution is e^(-1/3) (e tends to +0)...Can anyone explain this to me??
Sams as the right region...Please kindly help