At what frequency does the rotating mirror need to turn?

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Homework Help Overview

The discussion revolves around a problem involving a rotating mirror with 16 sides used to measure the time it takes for light to travel a distance of 3.5 km to a concave mirror and back. Participants are exploring the frequency at which the mirror must rotate to complete 1/16th of a rotation during this time interval.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to calculate the time taken for light to travel the specified distance and are questioning the correctness of their algebraic manipulations. There is discussion about whether the formula for time should be t = d/c or t = dc, and participants are analyzing unit consistency in their calculations.

Discussion Status

The discussion is active, with participants questioning the reasonableness of the calculated time for the light's round trip and engaging in unit analysis to clarify their understanding. There is no explicit consensus on the correct approach yet, as participants are still exploring the implications of their calculations.

Contextual Notes

Participants are grappling with the implications of their calculations, particularly regarding the time taken for light to travel the specified distance and the relevance of units in their formulas. The original poster expresses uncertainty about the correctness of their approach.

dannie
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A rotating mirror with 16 sides was used to measure the tine it took light to travel 3.5km to a concave mirror and back. At what frequency did the rotating mirror need to turn to make 1/16th of a rotation in the time it took light to travel to 3.5km and back again?



im having a bit of trouble with the second part. is this correct?


d=3.5x10^3m x 2
=7x10^3m
c=speed of light
=3 x 10^8 m/s
c=d/t
t=c/d
t=3x10^8m/s/ 7x10^3m
=4.28x10^4 s

t= 1/8 T
T= t/(1/8)
=4.28x10^4s/(1/8)
=3.42x10^5 s


T=1/f
f= 1/T
=1/(3.42x10^5)
=2.92x10^-6s
 
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dannie said:
A rotating mirror with 16 sides was used to measure the tine it took light to travel 3.5km to a concave mirror and back. At what frequency did the rotating mirror need to turn to make 1/16th of a rotation in the time it took light to travel to 3.5km and back again?



im having a bit of trouble with the second part. is this correct?


d=3.5x10^3m x 2
=7x10^3m
c=speed of light
=3 x 10^8 m/s
c=d/t
t=c/d <---- check your algebra!
t=3x10^8m/s/ 7x10^3m
=4.28x10^4 s
Does that time for the round trip of the light seem reasonable to you? It's nearly half a day!
 
ok so is it rather. t= d/c?
 
gneill said:
Does that time for the round trip of the light seem reasonable to you? It's nearly half a day!
so is it rather t= d/c or t=dc?
 
dannie said:
so is it rather t= d/c or t=dc?

What does units analysis tell you? What are the units of distance, speed?
 
gneill said:
What does units analysis tell you? What are the units of distance, speed?

time= speed of sound/distance or
s= m/s / m
dont the the meters cancel out? giving seconds?
 
dannie said:
time= speed of sound/distance or
s= m/s / m
dont the the meters cancel out? giving seconds?

Do the seconds end up in the numerator or the denominator? And what's with the "speed of sound"? There's no sound involved here. You just need to invoke the base units: m,kg,s.

If you want to end up with units of time, then time better end up in the numerator :wink:
 

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