At what rate must the current be to changed to produce 40V emf

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To produce a 40 V emf in a 20 H inductor, the rate of change of current (di/dt) must be calculated using the formula EMF = -L di/dt. The steady current of 4.0 A indicates that the current is not changing, meaning di/dt is effectively zero in that context. Therefore, the steady current information is not directly relevant to finding the required di/dt for the emf. The correct calculation involves rearranging the formula to di/dt = -EMF/L, leading to a necessary change in current to achieve the desired emf. The discussion highlights the importance of correctly applying the formula and recognizing the implications of steady current on di/dt.
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A 20 H inductor carries a steady current of 4.0 A. At what rate must the current be changed to produce a 40 V emf in the inductor?

I odn't get this one because it gives you all the information!
The formula is:
EMF = -L di/dt
they want u to find di/dt, but they already give you it has a steady current of 4.0A, so isn't di/dt just i, which is 4.0A?
Then the EMF would be 40, and they say L = 20H, so I'm stuck on what intermediate step I'm missing! thanks
 
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For a steady current, at any value,

\frac {dI} {dt} = 0
 
So basically, I can disregard that they told me it had a steady current of 4.0A right? and then just use
di/dt = EMF/-L to find the di/dt?
 
thanks that was the trick! i did that the last time, but forgot the minus sign!
 
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