Atomic Mass of Element X in XCl3 Stoichiometry Problem

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To find the atomic mass of element X in XCl3, given that 6.08 g of XCl3 contains 1.37 g of X, the remaining mass of Cl is calculated to be 4.71 g. The moles of Cl can be determined by dividing 4.71 g by the molar mass of Cl (35.5 g/mol), resulting in approximately 0.133 moles of Cl. Since the stoichiometric ratio of X to Cl in XCl3 is 1:3, the moles of X can be calculated as one-third of the moles of Cl, yielding about 0.044 moles of X. Finally, the atomic mass of X can be derived by dividing the mass of X (1.37 g) by its moles (0.044), leading to an atomic mass of approximately 31.14 g/mol.
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Homework Statement



What is the atomic mass of element X if 6.08 g XCl3 contains 1.37 g of X

Homework Equations





The Attempt at a Solution



(6.08 g XCl^3)*(1 mol X/107.729 g *XCl3)*(1.37 g X/1 mol X)=.077 g of X

That can't be right , because 1.37 g of X can't be included in the molar mass of XCl3
 
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Long time since passed since doing stoichiometry exercises...

Total XCl3 was 6.08, since grams X was 1.37, amount of Cl mass was 4.71 grams.

How many formula units Cl ? 4.71/(35.5);
Ratio of X formula units to Cl formula units = 1/3

How many moles of X ? ((4.71)/(35.5))*(1/3)

Now you have calculated moles of X or formula units of X, and were given grams of X.
Finish the calculation.
 
Roco, your answer was correct, but we can't go about handing out complete solutions to homework questions.

Benzoate, to simplify symbolipt's method a wee bit...

Answer this question: If there's 4.71 gms of Cl3 and 1.37 gms of X (in a sample of XCl3), what is the formula mass of X?
 
Gokul43201 said:
Roco, your answer was correct, but we can't go about handing out complete solutions to homework questions.

Benzoate, to simplify symbolipt's method a wee bit...

Answer this question: If there's 4.71 gms of Cl3 and 1.37 gms of X (in a sample of XCl3), what is the formula mass of X?
sorry! will comply.
 

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