Attack of my horrid math skills, pt. 1

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Discussion Overview

The discussion revolves around the differentiation of a mathematical function, specifically focusing on the application of the chain rule in calculus. Participants analyze a derivative calculation presented in a book, addressing potential errors and clarifications related to the notation and terms used.

Discussion Character

  • Technical explanation

Main Points Raised

  • One participant questions the appearance of the term 2x in the derivative, suggesting that it should not be there if the derivative is taken correctly.
  • Another participant confirms that the term arises from the chain rule, implying that the differentiation process is valid.
  • A third participant agrees with the use of the chain rule but points out a potential confusion between the variables x and b in the derivative expression.
  • A later reply acknowledges the mistakes as typos and expresses a light-hearted attitude towards the confusion.

Areas of Agreement / Disagreement

There is some agreement on the application of the chain rule, but participants express differing views on the correctness of the variable usage in the derivative. The discussion remains somewhat unresolved regarding the clarity of the original function's notation.

Contextual Notes

Limitations include potential confusion over variable notation and the implications of typos in mathematical expressions, which may affect the interpretation of the derivative.

moe darklight
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I thought I should start numbering these... anyway, here's another brain-fart where I miss something obvious:

in the book the dude uses:

[tex]\[<br /> f(x) = \frac{1}{{30}}\sqrt {a^2 + x^2 } + \frac{1}{{60}}(b - x)<br /> \][/tex]

later on he continues, using:

[tex]\[<br /> f'(x) = \frac{1}{{30}}\frac{1}{2}(a^2 + x^2 )^{ - 1/2} (2x) - \frac{1}{{60}}<br /> \][/tex]

where'd that 2x come from? isn't the derivative of [tex]\[<br /> \sqrt {a^2 + x^2 } <br /> \][/tex] just [tex]\[<br /> \frac{1}{2}(a^2 + x^2 )^{ - 1/2} <br /> \][/tex]?

thanks :biggrin:
 
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Well assuming that you mean x instead of b, that 2x comes from the chain rule.
 
yea chain rule but also he seems to have confused x for b in the derivative, should be [tex]\frac{1}{2}(a^2+x^2)^{-1/2}(2x)[/tex]
 
blah, I'm an idiot :smile: . o well, haha thanks.

and yea those two were typos; I fixed them.
 

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