Atwood Machine, two masses + two pulleys (w/ mass)

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SUMMARY

The discussion focuses on solving an Atwood machine problem involving two masses and two pulleys. The left wheel has a mass of 2.1 kg and a radius of 21.44 cm, while the right wheel has a mass of 2.8 kg and a radius of 33.94 cm. The hanging masses are 1.53 kg on the left and 1.13 kg on the right. The final acceleration formula derived is a = (g(m3 - m4)) / (m1 + m2 + m3 + m4), which incorporates gravitational force and the total mass of the system.

PREREQUISITES
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  • Familiarity with torque equations
  • Basic knowledge of gravitational force calculations
  • Ability to manipulate algebraic equations for solving unknowns
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  • Learn about the derivation of torque equations in mechanical systems
  • Explore advanced Atwood machine variations and their applications
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of Atwood machines in problem-solving contexts.

destrow111
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Homework Statement


An Atwood machine is constructed using two
wheels (with the masses concentrated at the
rims). The left wheel (m1) has a mass of 2.1 kg and
radius 21.44 cm. The right wheel (m2) has a mass
of 2.8 kg and radius 33.94 cm. The hanging
mass on the left (m3) is 1.53 kg and on the right (m4)
1.13 kg.



Homework Equations


Sum of Torque1= (m3)g(r1) - T(r1) = (m1)(r1)a
Sum of Torque2= T(r2) - (m4)g(r2) = (m2)(r2)a


The Attempt at a Solution


used subsitution to solve for a...
a = ((m3)g - (m4)g) / ((m1) + (m2))
 
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welcome to pf!

hi destrow111! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)
destrow111 said:
Sum of Torque1= (m3)g(r1) - T(r1) = (m1)(r1)a
Sum of Torque2= T(r2) - (m4)g(r2) = (m2)(r2)a

i'm not sure what the set-up is, but looking at those two equations, if T is an unknown, then you need to eliminate T …

how would you do that? :smile:
 


I actually figured it out!

there were actually three different tensions so i added sum of forces equations for each of the masses then subsituted a couple times until acceleration was the only unknown!

ended up being a = (g(m3 - m4)) / (m1 + m2 + m3 + m4)
 

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