Autonomous DE Question: Solving for the Limit of y(t) | Initial Value Problem

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SUMMARY

The discussion centers on solving the initial value problem defined by the differential equation dy/dt = y(1 - 0.0005y) with the initial condition y(0) = 1. The limit as t approaches infinity for y(t) is determined by analyzing the behavior of the function rather than directly solving the integral. Participants emphasize the importance of understanding the function's increasing and decreasing behavior and identifying turning points to predict the equilibrium value of y(t) as it stabilizes over time.

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Homework Statement


Suppose that y(t) is a solution of the initial value problem
dy/dt = y(1-.0005y) , y(0) = 1
What is the limit \lim_{t\to\infty}y(t)

The Attempt at a Solution



If I try just separating it to solve for y(t) then I get \int{{dy}/{(y-.0005y^2)}} = x+C which I can't figure out how to solve. I'm at a loss as to what else to do. Is there some way I should be able to predict the behaviour of the function with just the initial value and the DE, or am I missing something about how to evaluate the integral or solve the DE? I tried predicting what the function would do based on what I was given, but I got the wrong answer and figured it was because I was doing it based on the y values, but not knowing the actual function I didn't know which y values would occur as t went to infinity.
 
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You can solve the DE by using partial fraction decomposition, but that isn't really necessary here.

Instead, look at where y(t) is increasing/decreasing and what turning points it has. Start by looking at t=0 - is the function increasing or decreasing there? A small time later, is the function increasing or decreasing? Does it eventually reach some turning point and start increasing/deceasing towards some finite value as t \to \infty?
 
Ah, I see it now. I was getting a little mixed up with the y's and the t's, and I wasn't thinking about the fact that once it settles into an equilibrium value it's not going to change anymore. Thanks.
 

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