Average force of air resistance

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SUMMARY

The discussion focuses on calculating the average force of air resistance experienced by a space shuttle glider during its descent. The glider, with a mass of 1500 kg, was launched horizontally at 750 km/h from a height of 4500 m and landed at a speed of 300 km/h. The calculations involved converting initial and final velocities to meters per second and applying energy conservation principles. The final result for the average force of air resistance was determined to be 3608 N after correcting initial errors in the equations used.

PREREQUISITES
  • Understanding of kinematic equations and energy conservation principles
  • Familiarity with nonconservative forces in physics
  • Ability to convert units (e.g., km/h to m/s)
  • Knowledge of basic trigonometry, specifically sine and cosine functions
NEXT STEPS
  • Study the principles of energy conservation in nonconservative systems
  • Learn about the effects of air resistance on projectile motion
  • Explore advanced kinematic equations for varying angles of descent
  • Investigate the impact of mass and velocity on air resistance calculations
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Physics students, aerospace engineers, and anyone interested in understanding the dynamics of air resistance in flight mechanics.

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[SOLVED] Average force of air resistance

In early test flights for the space shuttle using a "glider" (mass of 1500kg including pilot), it was noted that after a horizontal launch at 750km/h at a height of 4500m, the glider eventually landed at a speed of 300km/h. What would it's landing speed have been in the absence of air resistance? What was the average force of air resistance exerted on the shuttle if it came in at a constant angle of 10 degrees to the earth?

I converted vi to 208.33 m/s and vf to 83.33 m/s.

I think I answered the first part correctly using 1/2mvi^2 + mgyi = 1/2mvf^2 + mgyf. I calcualted vf = 362.77 m/s. I double checked this using kinematic equations and got the same answer.

I'm having problems with the second part. I believe air resistance is a nonconservative force. The only equation that I came up with is:

wnc = change in KE + change in PE

From this I derived:

Fyi cos 10 = 1/2mvf^2 - 1/2mvi^2 + mgyf - mgyi

Using this I came up with the answer -21097 N but this doesn't seem right. What am I missing here?
 
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I think I figured out where I went wrong.
d = yi/sin 10 making w = Fdcos 180 = -Fd = -F(yi/sin 10)

This would give me the following equation:

-F(yi/sin10) = (1/2mvf^2 - 1/2mvi^2) + (mgyf - mgyi)

Then solve for F. F = 3608N
 

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