To start right at the beginning the problem is to find an expression for the pressure (force) due to molecules colliding with a wall.
Consider a molecule of mass m moving with speed (velocity) c inside a container of dimensions l x a x b (volume = lab)
The molecule strikes face ab and rebounds perfectly elastically so change in
momentum = 2mc
Force on face ab = change in momentum x Number of collisions per second
so force due to 1 molecule = 2mc/(2l/c) = mc2/l
So pressure on ab due to 1 molecule = mc2/lab = mc2/V
If there are N molecules in the container then, on average, N/3 move in the x, y and z directions.
Therefore pressure on ab due to N molecules = Nmc2/3V
or PV = Nmc2/3
Now KE of molecules = mc2/2 so PV = 2N(KE)/3
If there is 1 mole of molecules then N = Na
Therefore PV = 2Na x KE/3 for 1 mole
You also know that PV = RT for 1mole
so 2Na x KE/3 = RT
This give KE = 3/2 RT/Na
R/Na is a ratio of 2 constants and is known as Boltzmann's constant, k.
I hope that this is MORE than what you needed.