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Average kinetic energy of molecules

  1. Apr 30, 2013 #1

    The formula for average kinetic energy of molecule is:


    Can anyone please explain the derivation without using calculus?


    -- Shounak
  2. jcsd
  3. Apr 30, 2013 #2

    Andy Resnick

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    Each degree of freedom contains 1/2 kT of energy; for point objects there are only 3 degrees of freedom. Diatomic molecules have 5 degrees of freedom
  4. Apr 30, 2013 #3


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    Staff: Mentor

  5. Apr 30, 2013 #4
    To start right at the beginning the problem is to find an expression for the pressure (force) due to molecules colliding with a wall.
    Consider a molecule of mass m moving with speed (velocity) c inside a container of dimensions l x a x b (volume = lab)
    The molecule strikes face ab and rebounds perfectly elastically so change in
    momentum = 2mc
    Force on face ab = change in momentum x Number of collisions per second
    so force due to 1 molecule = 2mc/(2l/c) = mc2/l
    So pressure on ab due to 1 molecule = mc2/lab = mc2/V
    If there are N molecules in the container then, on average, N/3 move in the x, y and z directions.
    Therefore pressure on ab due to N molecules = Nmc2/3V
    or PV = Nmc2/3
    Now KE of molecules = mc2/2 so PV = 2N(KE)/3
    If there is 1 mole of molecules then N = Na
    Therefore PV = 2Na x KE/3 for 1 mole
    You also know that PV = RT for 1mole
    so 2Na x KE/3 = RT
    This give KE = 3/2 RT/Na
    R/Na is a ratio of 2 constants and is known as boltzman's constant, k.

    I hope that this is MORE than what you needed.
  6. Apr 30, 2013 #5
    Thank you very much for the derivation. The N/3 factor comes into play due to the x,y,z three directions, right?
  7. Apr 30, 2013 #6
    In addition the equation should have an 'average' velocity known as the root mean square velocity.
    I did not include that to keep the typing as simple as possible.
    Also the KE is called TRANSLATIONAL KINETIC ENERGY. There are other kinetic energies (rotational and vibrational) but it is translational KE that 'shows' as Temperature
  8. Apr 30, 2013 #7
    Hello Technician,

    Thank you very much for all the reply.
  9. May 1, 2013 #8
    Hello jtbell,

    I have just one small thing to ask you. The link that you have provided tells, the ideal gas law PV=nRT which is again:PV=2/3N(1/2mv^2).

    Can you please show me how it came?

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