Average of function (using dirac delta function)

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The discussion focuses on computing the average value of the function f(x) = δ(x-1)*16x^2sin(πx/2)*eiπx/(1+x)(2-x) over the interval [0, 8]. The key equation used is the property of the Dirac delta function, which simplifies the integral to f(1) when evaluated at the point where the delta function is centered. The average is calculated as -1, but there is confusion regarding the application of the delta function and the negative sign in the expression. Clarification is provided that the parameter 'a' in δ(x-a) is indeed 1, not -1, confirming the correct evaluation of the function at that point. The final conclusion is that the average value computed is correct despite initial uncertainties.
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Homework Statement


Compute the average value of the function:

f(x) = δ(x-1)*16x2sin(πx/2)*eiπx/(1+x)(2-x)

over the interval x ∈ [0, 8]. Note that δ(x) is the Dirac δ-function, and exp(iπ) = −1.

Homework Equations


∫ dx δ(x-y) f(x) = f(y)

The Attempt at a Solution


Average of f(x) = 1/8 ∫from 0 to 8 δ(x-1) dx 16x2sin(πx/2)*(-1)/(1+x)(2-x)
Average of f(x) = -1

Is this correct? I'm unsure of whether you can just use δ(x-a) = δ(x-1) and let a=1 and not let a=-1? I don't get how to use this bit of the function as I seem to have just ignored the negative sign.

Many thanks.
 
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From the problem statement, your a is = to 1 not -1.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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