Average power dissipated in resistor

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The discussion revolves around calculating the average power dissipated in a 30 Ω resistor within a circuit driven by a current source ig=7cos(20,000t) A. Participants emphasize the importance of using the RMS current for accurate power calculations, noting that the peak current must be converted to RMS for proper results. Confusion arises regarding mesh currents and the correct equations to apply, particularly in relation to dependent and independent sources in the circuit. Ultimately, the calculated RMS current leads to a power dissipation result of approximately 817 W, confirming the accuracy of the final calculations. The conversation highlights the complexities of mesh analysis in circuits with both independent and dependent sources.
  • #31
(j30)I = (210 - j70)
I = -2.333 - 7j
I = 7.3786 A
Arms = 5.2175 A
P = 816.66 W
 
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  • #32
Looks good.
 
  • #33
Jesus thank you. Two pages of trying to figure out a simple mesh . . . Ugh . . .But 817 W is correct! Try number 1, 80% total on the homework.
 

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