Average power dissipated in resistor

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SUMMARY

The average power dissipated in a 30 Ω resistor in a circuit with a current source ig=7cos(20,000t) A is calculated using mesh analysis. The correct approach involves determining the RMS current through the resistor, which is derived from the peak current ig. The final calculation yields an average power of 816.66 W, confirming the accuracy of the mesh equations and the substitution of currents. The key equations utilized include P=I^2(R) and the relationships between mesh currents.

PREREQUISITES
  • Understanding of mesh analysis in electrical circuits
  • Familiarity with RMS and peak current calculations
  • Knowledge of KVL (Kirchhoff's Voltage Law) and KCL (Kirchhoff's Current Law)
  • Basic concepts of complex impedance in AC circuits
NEXT STEPS
  • Study mesh analysis techniques in more complex circuits
  • Learn about calculating RMS values from peak values in AC circuits
  • Explore the implications of dependent sources in circuit analysis
  • Investigate power factor and its effect on power calculations in AC circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits and power dissipation in resistive components.

  • #31
(j30)I = (210 - j70)
I = -2.333 - 7j
I = 7.3786 A
Arms = 5.2175 A
P = 816.66 W
 
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  • #32
Looks good.
 
  • #33
Jesus thank you. Two pages of trying to figure out a simple mesh . . . Ugh . . .But 817 W is correct! Try number 1, 80% total on the homework.
 

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