Average Velocity and Acceleration Calculations for Walking Man

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The discussion revolves around calculating average velocity and acceleration for a man walking at a constant speed after standing still. The user attempts to solve four problems related to average velocity and acceleration over specified time intervals but receives feedback indicating errors in their calculations. Key points of confusion include the use of time intervals and the rationale behind dividing by 60 in the acceleration calculations. Clarifications are sought regarding the correct approach to determine average velocity and acceleration, particularly the choice of time intervals used in the formulas. Understanding these concepts is essential for accurately solving the homework problems.
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Homework Statement



From t = 0 to t = 5.00 min, a man stands still, and from t = 5.00 min to t = 10.0 min, he walks briskly in a straight line at a constant speed of 1.9 m/s.

Homework Equations



(a) What is his average velocity vavg in the interval 2.000 min to 7.60 min? ___m/s

(b) What is his average acceleration aavg in the interval 2.00 min to 7.60 min? ___m/s2

(c) What is vavg in time 3.00 min to 9.00 min? ___m/s

(d) What is aavg in time 3.00 min to 9.00 min? ___m/s2


The Attempt at a Solution



a) 1.9*2.6/5.6 = .882 m/s right

b) 1.9/5.6/60 = .006 m/s2 wrong

c) 1.9*2.6/7 = .707 m/s wrong

d) 1.9/6/60 = .005 m/s2 wrong

Where did I go wrong?
 
Physics news on Phys.org
how do you determine average velocity and average acceleration?
why are you dividing by 60 in b and d?
where did you get the 2.6/7 in c?
compare - how did you get the 2.6 and the 5.6 in a?
 
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