Average velocity from multiple displacement/velocities

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SUMMARY

The discussion centers on calculating the average speed of a car traveling different distances at varying speeds: 60 kph for 30 km, 40 kph for another 30 km, and 50 kph for the final 30 km. The incorrect assumption that averaging the speeds directly yields the correct average speed is clarified. The correct method involves calculating total time using the formula (d1/v1 + d2/v2 + d3/v3), resulting in a total time of 1.85 hours, leading to an average speed of 48.65 kph when total displacement is divided by total time. The conclusion emphasizes that equal time intervals are necessary for simple averaging to be valid.

PREREQUISITES
  • Understanding of average speed calculations
  • Familiarity with basic physics concepts of velocity and displacement
  • Ability to perform unit conversions and time calculations
  • Knowledge of the formula for average speed: total displacement/total time
NEXT STEPS
  • Study the concept of weighted averages in physics
  • Learn about the implications of varying speeds on average velocity
  • Explore problems involving average speed with unequal distances and times
  • Investigate the relationship between distance, speed, and time in different scenarios
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This discussion is beneficial for students studying physics, educators teaching kinematics, and anyone interested in understanding the nuances of average speed calculations in real-world scenarios.

BogMonkey
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Heres the problem:
"A car travels at a constant speed of 60kph for 30km, 40kph for another 30km and 50kph for the final 30km. What is the average speed of the car."

I know that in this case I can just add the velocities and divide by 3 since the displacements are equal and get 50kph as the average speed but when I tried to do it the long way I didn't get the same answer. First I calculated the total time elapsed like this d1/v1 + d2/v2 + d3/v3 and got t = 1.85h. Then to get the average speed I divided the total displacement by time (90/1.85) and got 48.65kph.

there's a pattern there I've tried this with various problems and I always a little less than the right answer. Whats going on here?
 
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BogMonkey said:
I know that in this case I can just add the velocities and divide by 3 since the displacements are equal and get 50kph as the average speed
Although it might seem right, it's not. You really need to find total displacement over time.

Now if the time intervals were equal, then it would work. :wink:
 

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