Average Velocity from V-T Graph w/ Non-Constant Accel.

AI Thread Summary
To find average velocity from a velocity vs. time graph with non-constant acceleration, calculate the area under the graph between the specified time intervals, t1 and t2, which represents the total distance traveled. The average velocity is then determined by dividing this total distance by the total time elapsed, expressed as average velocity = total distance / total time. This method effectively accounts for varying acceleration by focusing on the area under the curve. Understanding this concept is crucial for accurately interpreting motion in physics. The approach provides a clear framework for analyzing average velocity in scenarios involving non-constant acceleration.
assuredlonewo
Messages
15
Reaction score
0
How does one get the average velocity from a velocity vs. time graph, when acceleration is not constant.
 
Physics news on Phys.org


If you have a velocity -time graph the area under it is the distance traveled between t1 and t2

The average velocity is
{\rm{average velocity = }}\frac{{{\rm{total distance}}}}{{{\rm{total time}}}}{\rm{ = }}\frac{{{\rm{Area under graph between }}{{\rm{t}}_{\rm{1}}}{\rm{and }}{{\rm{t}}_{\rm{2}}}}}{{{{\rm{t}}_{\rm{2}}}{\rm{ - }}{{\rm{t}}_{\rm{1}}}}}
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top