DrDu said:
Ok, I understand.
Another question: Is it necessary to have a non-abelian gauge field to obtain an anomaly? I mean in general and not necessarily the axial anomaly. Would a U(1) not do?
chrispb said:
U(1) symmetries can indeed be anomalous.
The axial anomaly of nonabelian gauge theories actually comes from a broken U(1) symmetry.
In QCD, you have [itex]U(N_f)_L\times U(N_f)_R[/itex] chiral symmetry, with both a conserved left-handed current [itex]L^\mu[/itex] and a right-handed one, [itex]R^\mu[/itex]. It is now possible to make a linear combination of those two currents, leading to a vector current [itex]V^\mu=(L^\mu+R^\mu)/2[/itex] and an axial current [itex]A^\mu=(L^\mu-R^\mu)/2[/itex] (note: [itex]A^\mu[/itex] is not the gauge field). The symmetry group is now [itex]U(N_f)_V\times U(N_f)_A[/itex], which is isomorphic to the original one. It now decomposes as
[itex]U(N_f)_V\times U(N_f)_A\equiv U(1)_V\times SU(N_f)_V\times U(1)_A\times SU(N_f)_A.[/itex]
You can now analyze each part separately, and see what it does. You get the following results:
[itex]U(1)_V[/itex] remains unbroken, it stands for baryon-number conservation.
[itex]SU(N_f)_V[/itex] is broken in the case when quarks have different masses.
[itex]SU(N_f)_A[/itex] is broken when quarks have nonzero mass.
[itex]U(1)_A[/itex] is broken at quantum level for non-vanishing quark masses, that's what is referred to as chiral/axial anomaly.