Ball Drop Problem: Solving the Dual Impact Challenge

  • Thread starter Thread starter ArbazAlam
  • Start date Start date
  • Tags Tags
    Ball Drop
AI Thread Summary
To solve the Ball Drop Problem, first calculate the time it takes for the second ball, dropped 2 seconds after the first, to hit the ground from a height of 60 meters. The equation of motion for the dropped ball can be used to determine this time. Once the time for the dropped ball is established, use it to find the required initial speed of the first ball so that both balls hit the ground simultaneously. The key is to relate the displacement of the first ball, which is thrown upwards, to the time it travels. Understanding these equations of motion is crucial for solving the problem effectively.
ArbazAlam
Messages
10
Reaction score
0
This problem has really been bugging me. After several attempts, I don't even know where to start anymore.

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof 2.00 s later. Air resistance may be ignored.

(a) If the height of the building is 60 m, what must be the initial speed of the first ball if both are to hit the ground at the same time?
 
Physics news on Phys.org
Well the first thing i would do is calculate the time it takes for the dropped ball to hit the ground. That should be a fairly simple calculation.

Next, what equation do you know which relates the displacement of an accelerating body to the time it travels for?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top