Ball Up Incline: Total Energy & Height Q&A

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Total energy in the context of a rolling sphere includes both translational and rotational kinetic energy, expressed as KE = 1/2mv^2 + 1/2Iw^2. The equation PE = 1/1*Iw^2 mentioned was likely a typographical error, as it should represent rotational kinetic energy. The potential energy is typically calculated using mgh, which is standard for height-related energy calculations. The discussion clarifies that for a rolling object, total energy encompasses both forms of kinetic energy due to its motion. Understanding these concepts is crucial for accurately determining the total energy and height of the ball on the incline.
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what I'm looking for is 1. the total energy of the sphere, and 2. the height of the ball after it has traveled up the incline.

i have some questions however. First, i understand that total energy = KE+PE. looking at the solution, KE=1/2mv^2. why does PE=1/1*Iw^2? this is the first time I've ever seen PE defined as such an equation.

in the second part of the solution, they use mgh - why isn't mgh used in the first solution? thanks
 
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mikefitz said:
i have some questions however. First, i understand that total energy = KE+PE. looking at the solution, KE=1/2mv^2. why does PE=1/1*Iw^2? this is the first time I've ever seen PE defined as such an equation.

The term 'PE=1/1*Iw^2' you were referring to was supposed to be the rotational kinetic energy of the sphere, which equals 1/2 I w^2, so I assume it was a mistype. You're right - total energy is defined as the sum of potential and kinetic energy - but, since you have a rolling sphere, the kinetic energy is the sum of rotational and translational kinetic energy.
 
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