Ballistic Pendulum: Bullet Impact at 500m/s

AI Thread Summary
A ballistic pendulum is analyzed where a bullet traveling at 500 m/s passes through a 1 kg wooden block hanging from a 2.5 m string, causing the block to swing to a maximum angle of 12 degrees. The initial velocity of the block after the bullet passes is recalculated to be 0.98 m/s, while the initial momentum of the bullet is corrected to 3 kg-m/s. Discussions focus on determining the final velocity of the bullet after it exits the block, with estimates around 327 m/s to 333.333 m/s. Participants emphasize the need for accurate calculations of the block's height change and momentum. The conversation highlights the importance of precision in physics problems involving conservation of energy and momentum.
rsala
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Homework Statement


a ballistic pendulum is hit by a bullet traveling 500m/s , the ballistic pendulum is a block of wood hanging from a string.
the block of wood (1kg) is hanging from the string of 2.5m
the bullet has mass .006kg @ 500m/s
the bullet passes right through the block of wood before it makes any significant movement.
the block of wood swings to a max angle of 12 degrees with the vertical.

ive drawn out a microsoft paint image.
http://img512.imageshack.us/img512/262/bulletib5.jpg

Homework Equations


conservation of energy
and momentum

The Attempt at a Solution



here is my solution
please tell me if i got the correct answer, this is from a test i took yesterday

http://img246.imageshack.us/img246/5002/bullet2lv3.jpg

edit : I've made changes,, the correct initial velocity of the block .98 m/s
and the bullets initial momentum is 3 kg-m/s
and the final bullet velocity is 333.333,, is this correct?
thank you
 
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I assume the problem is to find the speed of the bullet after it passes through the block.

No, it's not correct.

(1) Recalculate a more accurate value for the change in height of the block.

(2) Recalculate the initial (post bullet) velocity of the block.

(3) Recalculate the initial momentum of the bullet. (It's not 6 kg-m/s.)
 
I see i made the mistake, the velocity of the block initially should be .98 m/s NOT 3.13

ic the wrong bullet momen. now, it is 3

so should the final velocity of the bullet be 333.3333 m/s?


or is it 327, ?
thank you
 
Last edited:
rsala said:
I see i made the mistake, the velocity of the block initially should be .98 m/s NOT 3.13
I get a slightly different value for the velocity.

ic the wrong bullet momen. now, it is 3
Right.

so should the final velocity of the bullet be 333.3333 m/s?
That's close to what I get.

or is it 327, ?
That's even better. :approve:
 
i wrote 333.333 on the test
now i don't know what to say, whether it got it wrong or not
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
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