Band structures with non-primitive cells

erst
Messages
21
Reaction score
0
How does one interpret band structures (i.e. E,k solution pairs for a given Hamiltonian) for a non-primitive cell? I was looking at these slides: http://www.tcm.phy.cam.ac.uk/castep/CASTEP_talks_06/clark2.pdf

Slide 9 has the "normal" silicon band structure obtained with a primitive cell. Slide 11 uses a cubic cell and obtains a different band structure. Do they somehow contain equivalent information? I know zones fold over, but the non-primitive band structure actually seems to have a direct band gap at Gamma, while Si is known to have an indirect gap. How was this information lost?
 
Physics news on Phys.org
Dear, erst
I have some problem like you ...
I've calculated the band structure of si by mathematica.
I could plot non-primitive bandstructure (slide 11). (by psudopotential coefficients)
It is true.

I couldn't calculate the slide 9.

I ussing thease deffinitions for non-primitive ...

kPosition[address_] := Module[{pos},
Which[address == "\[CapitalGamma]",
pos = {0, 0, 0};
, address == "X",
pos = {0, 1/2, 0};
, address == "M",
pos = {0, 1/2, 1/2};
, address == "R",
pos = {1/2, 1/2, 1/2};
];
pos];

I don't know why the gamma point=(0,0,0) has 4 eigenvalues in the slide 11 in valence bands but 2 eigenvalues in the slide 9. D-:
R={0..5,0.5,0.5} in the slide 11 is the L point in the slide 9.Mohammad
 
Last edited:
A larger unit cell in real space gives a smaller Brillouin zone in reciprocal space.

If, for example, the real space cell is 4 times larger than the primitive cell, then the Brillouin zone will be 4 times smaller.

Since it must contain the same information and describe the same number of electrons, that means you will get 4 times more bands.
At the BZ boundary, these bands will meet without gap. In fact, the extra band can be obtained by taking the larger BZ and folding the bands inward at the BZ boundary of the smaller BZ.

What is lost are the selection rules, e.g. it looks as if you could have a transition from an "unfolded" to a "folded" band. This is because you loose some information about the periodicity when you go from a small real space cell to a larger, non-primitive one.
 
Thank you very much M Quack for your post

I could calculate the primitive cell band structure by your guidance.

forgive me because of my poor English
 
From the BCS theory of superconductivity is well known that the superfluid density smoothly decreases with increasing temperature. Annihilated superfluid carriers become normal and lose their momenta on lattice atoms. So if we induce a persistent supercurrent in a ring below Tc and after that slowly increase the temperature, we must observe a decrease in the actual supercurrent, because the density of electron pairs and total supercurrent momentum decrease. However, this supercurrent...
Hi. I have got question as in title. How can idea of instantaneous dipole moment for atoms like, for example hydrogen be consistent with idea of orbitals? At my level of knowledge London dispersion forces are derived taking into account Bohr model of atom. But we know today that this model is not correct. If it would be correct I understand that at each time electron is at some point at radius at some angle and there is dipole moment at this time from nucleus to electron at orbit. But how...
Back
Top