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Bandwidth efficiency in m - ary psk

  1. Dec 5, 2011 #1
    In M-ary psk
    Rb=Rs*log M log with base 2
    Rb- bit rate
    Rs - symbol rate
    then bandwidth required for passband signal is B=Rs
    and bandwidth effeciency = Rb/B=log M log with base 2.
    Is the above formula for bandwidth efficiency correct ?
    But in simon haykin it is given that bandwidth efficiency is (log M )/2 log with base 2
     
  2. jcsd
  3. Dec 31, 2011 #2
    The channel bandwidth required to pass M-ary PSK is B=2/T
    Now, T = Tb (log2 M) and Rb = 1/Tb
    So rho = Rb/B = (log2 M) /2
     
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