- #1
fisico30
- 374
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Hello Forum,
the "maximum" data rate that can be used over a physical "noiseless" channel is given by
bits/s= 2*B* log2 M
where B is the channel bandwidth (set of frequencies that are passed with little attenuation), and M is the number of levels we can change the chosen parameter of the carrier signal that we modulate. We can increase the max bit rate by either increasing B or M.
If B is maintained fixed, we can increase the max data rate to infinity (in theory only of course). Let's say there is no noise and we have a baseband signal m(t) to be transmitted whose bandwidth is larger than the channel bandwidth: W>B...
Even if we can push the max data rate to whatever limit we want, what happens to the transmitted signal? Will it be smeared out regardless of the max data rate we have?
Of course we digitize the signal m(t) by sampling it at f>2W, and quantize the samples to get a stream of 1s and 0s. Example: W=30 Hz, B=5 Hz and the duration of m(t) is 20 seconds, and we quantize the sample so each one has 10 bits...
We get a total of 60*20*10=1200 bits...Now we need to transmit them through the channel whose bandwidth is simply 5 Hz and M=1000...What happens to the received bits?
thanks!
fisico30
the "maximum" data rate that can be used over a physical "noiseless" channel is given by
bits/s= 2*B* log2 M
where B is the channel bandwidth (set of frequencies that are passed with little attenuation), and M is the number of levels we can change the chosen parameter of the carrier signal that we modulate. We can increase the max bit rate by either increasing B or M.
If B is maintained fixed, we can increase the max data rate to infinity (in theory only of course). Let's say there is no noise and we have a baseband signal m(t) to be transmitted whose bandwidth is larger than the channel bandwidth: W>B...
Even if we can push the max data rate to whatever limit we want, what happens to the transmitted signal? Will it be smeared out regardless of the max data rate we have?
Of course we digitize the signal m(t) by sampling it at f>2W, and quantize the samples to get a stream of 1s and 0s. Example: W=30 Hz, B=5 Hz and the duration of m(t) is 20 seconds, and we quantize the sample so each one has 10 bits...
We get a total of 60*20*10=1200 bits...Now we need to transmit them through the channel whose bandwidth is simply 5 Hz and M=1000...What happens to the received bits?
thanks!
fisico30