# Banked Road Problem

1. Sep 30, 2007

### jrmed13

Okay, so I am doing a problem involving a car driving on a banked, frictionless, circular track (theta=31degrees) and i am supposed to find the maximum velocity that the car can drive. I know that to find the velocity, i have to find the centripetal acceleration by saying that (mv^2)/r = nsin(theta). Then, I have to solve for n by saying that ncos(theta)=mg. However, I am confused... why can't n=mgcos(theta)? My understanding is that two forces are equal in magnitude if the object doesn't move in either direction. The car doesn't move into the road or out of the road... or does it?? please help! I have a test on monday.

2. Oct 1, 2007

### learningphysics

It is true that the car doesn't move into the road or out of the road. However, the component of acceleration into the road is not 0.

In other words... suppose you take the $$\Sigma{F} = ma$$ equation perpendicular to the road. N - mgcos(theta) = ma... here a is not 0! this occurs because of the centripetal acceleration.