Basic linear motion question.Is it good?

AI Thread Summary
The discussion focuses on calculating the minimum runway length and acceleration for airplanes based on provided parameters. For the first scenario, a plane with a take-off speed of 65 m/s and an acceleration of 3 m/s² requires a minimum runway length of approximately 704.2 meters. In the second scenario, an airplane accelerating at 3.2 m/s² for 32.8 seconds travels a distance of 1721.3 meters before take-off. Lastly, for an airplane needing 1365 meters to reach a take-off speed of 88.3 m/s, the acceleration is calculated to be 2.856 m/s², taking about 30.9 seconds to reach that speed. Overall, the calculations demonstrate the relationships between speed, acceleration, and distance in runway design.
german1234
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Homework Statement


Airport runway designing:

(i)lowest acceleration rate of any plane is likely to be 3m/s^2.Take off speed for this airplane will be 65m/s.what is minimum allowed length of runway?

(ii)If airplane accelerates down runway at 3.2m/s^ for 32.8 seconds until it lifts off..determine distance traveled before take-off.

(iii)Another airplane has take off speed of 88.3m/s and needs 1365m to reach this speed.determine acceleration of plane and time taken to reach this speed.

Homework Equations


v=u+at

v^2=u^2+2as

s=ut+(1/2)at^2


The Attempt at a Solution




(i) a=3
u=0
v=65
s=? v^2=u^2+2as

65^2=0^2+2(3)s
4225=6s
s=4225/3
s= 704.2 m

(ii) a=3.2
t=32.8
u=0
s=?
s=ut+(1/2)at^2

s=0(32.8)+(1/2)(3.2)(32.8)^2

s=1721.3m

(iii)v=88.3
u=0
s=1365
t=?

v^2=u^2+2as

(88.3)^2=0^2+2a(1365)

7796.89=2730a

a=2.856m/s^2

Now:
v=u+at

88.3=0+2.856(t)

t=30.9 seconds

Thanks in advance
 
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