Basic motion question.Am I correct?

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The discussion revolves around calculating the deceleration and stopping time for a car traveling at 50 km/h over a distance of 100 meters. The constant rate of deceleration is found to be approximately -0.9645 m/s², using the equation v² = u² + 2as. The time taken to stop is calculated to be 14 seconds, applying the formula v = u + at. The calculations are confirmed as correct by the original poster. Overall, the problem is solved accurately with the appropriate physics equations.
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Homework Statement



A car is traveeling at 50km/h.It has to stop over distance of 100m.
Find
(a) constant rate of deceleration neede
(b)time taken to stop

Homework Equations



v^2=u^2+2as
v=u+at


The Attempt at a Solution



(a) 50km/hr= 13.889m/s=u
v=0
s=100m
a= need to find

v^2=u^2+2as

0^2= (13.889)^2 +2a(100)
-192.9=200a
a=-0.9645 m/s^2

(b)
v=u+at
0=13.889-0.9645t
0.9645t=13.889
t=14 seconds
 
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Looks perfect to me.
 
Thank you so much, Doc Al
 

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