(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A car is traveeling at 50km/h.It has to stop over distance of 100m.

Find

(a) constant rate of deceleration neede

(b)time taken to stop

2. Relevant equations

v^2=u^2+2as

v=u+at

3. The attempt at a solution

(a) 50km/hr= 13.889m/s=u

v=0

s=100m

a= need to find

v^2=u^2+2as

0^2= (13.889)^2 +2a(100)

-192.9=200a

a=-0.9645 m/s^2

(b)

v=u+at

0=13.889-0.9645t

0.9645t=13.889

t=14 seconds

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# Homework Help: Basic motion question.Am I correct?

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