Basic motion question involoving kinematics

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SUMMARY

The forum discussion centers on a kinematics problem involving a car rolling backwards due to a partially failed handbrake. The car's velocity is 0.8 m/s, while the owner's running speed is 7 m/s. The key equation derived from the problem is D = 7T and d = 0.8T, leading to the conclusion that the time taken for the owner to reach the car is T = 25 / (7 - 0.8), which calculates to approximately 3.57 seconds.

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hunter45
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Hey everyone,

I have a question from a past exam paper that I was doing. I spent a lot of time trying to solve it, however I have failed.
I would appreiciate it if I got some assistance from a professional or someone that can answer it correctly.

Question:

A car is parked on the side of the road. The handbrake on the car partially fails causing it to roll backwards. The velocity of the car after it starts to move is 0.8 m/s.
The owner of the car is standing 25m in front of the car when they see it start to roll backwards. He runs at a velocity of 7 m/s. towards it. How long will it take for him to first reach the front of the car?
 
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In T seconds, man travels 7*T m which is same as distance traveled by car (0.8T) and additional 25 m.
D = 7T
d = 0.8T
D = 25 + d
 

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