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Homework Help: Basic projectile motion question

  1. Jan 31, 2014 #1
    If I can throw a ball on a level field with a range of 15 m, how high would the ball travel if the same throw was made vertically?

    Using the range equation, I found the velocity to be 12.1 m/s, and the final answer to be 7.5m. Is this correct?
  2. jcsd
  3. Jan 31, 2014 #2
    Yes it is 7.5m assuming 15m is the maximum attainable range with that velocity.

    P.S: You could have solved this question without finding the velocity (I think you get it)

  4. Jan 31, 2014 #3
    How could you have solved without finding the velocity? I get that there must be some type of relationship between the height and the maximum range, but I'm not sure I understand exactly what it is.
  5. Feb 1, 2014 #4
    The formula for maximum range of a projectile motion is [itex] \frac{u^{2}}{g}[/itex] ('u' being the velocity) whereas the maximum attainable height by a ball thrown vertically upwards = [itex] \frac{u^{2}}{2g}[/itex] (This can be derived using the kinematical equations). So the latter is half of the former. Got it now?
  6. Feb 1, 2014 #5
    Got it, thanks so much.
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