Basic projectile motion question

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Homework Help Overview

The discussion revolves around a basic projectile motion problem, specifically comparing the maximum height achieved by a ball thrown vertically to its range when thrown at an angle on a level field.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the maximum height and the range of a projectile, with some questioning how to derive height without calculating velocity. Others reference the formulas for range and height in projectile motion.

Discussion Status

There is an ongoing exploration of the relationship between height and range, with some participants providing insights into the relevant formulas. While some clarity has been achieved, there remains a level of uncertainty regarding the derivation and application of these concepts.

Contextual Notes

Participants are discussing the problem under the constraints of a homework context, which may limit the information available for deriving relationships between variables.

gorays1414
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If I can throw a ball on a level field with a range of 15 m, how high would the ball travel if the same throw was made vertically?

Using the range equation, I found the velocity to be 12.1 m/s, and the final answer to be 7.5m. Is this correct?
 
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Yes it is 7.5m assuming 15m is the maximum attainable range with that velocity.

P.S: You could have solved this question without finding the velocity (I think you get it)

Regards!
ADI
 
Adithyan said:
Yes it is 7.5m assuming 15m is the maximum attainable range with that velocity.

P.S: You could have solved this question without finding the velocity (I think you get it)

Regards!
ADI

How could you have solved without finding the velocity? I get that there must be some type of relationship between the height and the maximum range, but I'm not sure I understand exactly what it is.
 
gorays1414 said:
How could you have solved without finding the velocity? I get that there must be some type of relationship between the height and the maximum range, but I'm not sure I understand exactly what it is.

The formula for maximum range of a projectile motion is [itex]\frac{u^{2}}{g}[/itex] ('u' being the velocity) whereas the maximum attainable height by a ball thrown vertically upwards = [itex]\frac{u^{2}}{2g}[/itex] (This can be derived using the kinematical equations). So the latter is half of the former. Got it now?
 
Adithyan said:
The formula for maximum range of a projectile motion is [itex]\frac{u^{2}}{g}[/itex] ('u' being the velocity) whereas the maximum attainable height by a ball thrown vertically upwards = [itex]\frac{u^{2}}{2g}[/itex] (This can be derived using the kinematical equations). So the latter is half of the former. Got it now?

Got it, thanks so much.
 

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