Basic question regarding gravitational acceleration

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When a 1 kg mass is lifted, it experiences a gravitational force of approximately 9.81 N. To determine the downward velocity of the object when released from a height of 1 meter, standard kinematic equations for constant acceleration can be applied. The velocity can be calculated using V = gt, where g is the acceleration due to gravity. The time taken to reach the ground can be found using D = 1/2 gt². These equations assume no air resistance for simplicity.
Pogo Physics
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Hello,

I have a very basic physics question. If I lift a body of mass 1 kg into air, it will be attracted by a downward force F = mg = 98.1 N.

What I want to know is what would be the downward velocity of the object? If I release an object of mass 1 kg from a height of 1 m, with what equation can I find the velocity of the object or the time needed by the object to reach the earth?

Thank you.
 
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Pogo Physics said:
I have a very basic physics question. If I lift a body of mass 1 kg into air, it will be attracted by a downward force F = mg = 98.1 N.
I think you mean 9.81 N.

What I want to know is what would be the downward velocity of the object? If I release an object of mass 1 kg from a height of 1 m, with what equation can I find the velocity of the object or the time needed by the object to reach the earth?
Ignoring complications such as air resistance, the acceleration of a falling body is constant. So you can use any of the standard constant acceleration kinematic formulas. For example:

V = gt (gives the velocity as a function of time)
D = 1/2 gt2 (gives the distance as a function of time)
 

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